CVE-2007-6738

Medium

Description

pyftpdlib before 0.1.1 does not choose a random value for the port associated with the PASV command, which makes it easier for remote attackers to obtain potentially sensitive information about the number of in-progress data connections by reading the response to this command.

SeverityMedium
CVSS5.0
Exploit probability—
ProductG.rodola Pyftpdlib
PublishedOct 19, 2010
First seenOct 19, 2010

How to fix

Update
  • pyftpdlib0.1.1 or later

Affected products

ProductAffected versionsFixed in
g.rodola pyftpdlibv ≤ 0.1—
pyftpdlibPyPIv < 0.1.10.1.1

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